Glossary entry (derived from question below)
English term or phrase:
deghosting
Spanish translation:
Dejarlo igual y explicar el proceso (ver def.)
Added to glossary by
Gabriela Rodriguez
May 19, 2005 18:52
19 yrs ago
8 viewers *
English term
deghosting
English to Spanish
Other
Science (general)
a number of "deghosting" and water layer effect attenuation techniques are known in the art for use with OBCs
Proposed translations
(Spanish)
4 +3 | Yo lo dejaría igual y explicaría el proceso. Ver def. | Gabriela Rodriguez |
4 +3 | antifantasma | Ernesto de Lara |
3 | limpiar la señal- remover resonancias | Gabo Pena |
Proposed translations
+3
4 mins
Selected
Yo lo dejaría igual y explicaría el proceso. Ver def.
MARINE DEGHOSTING
The marine ghost presents a problem that is essentially insoluble; but because it is always with us, we need to understand how to do the best we can with it. Even if an airgun could emit a perfect impulse, the impulse would reflect from the nearby water surface, thereby giving a second pulse of opposite polarity. The energy going down into the earth is therefore a doublet when we would prefer a single pulse. Likewise, hydrophones see the upcoming wave once coming up, and an instant later they see the wave with opposite polarity reflecting from the water surface. Thus the combined system is effectively a second derivative wavelet (1,-2,1) that is convolved with signals of interest. Our problem is to remove this wavelet by deconvolution. It is an omnipresent problem and is cleanly exposed on marine data where the water bottom is hard and deep.
Theoretically, a double integration of the second derivative gives the desired pulse. A representation in the discrete time domain is the product of (1-Z)2 with $1+2Z+ 3Z^2+ 4Z^3+ 5Z^4+ \cdots $, which is 1. Double integration amounts to spectral division by $-\omega^2$.Mathematically the problem is that $-\omega^2$ vanishes at $\omega=0$.In practice the problem is that dividing by $\omega^2$ where it is small amplifies noises at those low frequencies. (Inversion theorists are even more frustrated because they are trying to create something like a velocity profile, roughly a step function, and they need to do something like a third integration.) Old nuts like this illustrate the dichotomy between theory and practice.
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Note added at 5 mins (2005-05-19 18:57:58 GMT)
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sepwww.stanford.edu/sep/ prof/pvi/ls/paper_html/node19.html
--------------------------------------------------
Note added at 5 mins (2005-05-19 18:58:32 GMT)
--------------------------------------------------
Data Association for
Deghosting in Y-Shaped
Passive Linear Array Sonars
BONHWA KU
JEHAN YOON
Korea University
DAVID K. HAN
Johns Hopkins University
HANSEOK KO, Senior Member, IEEE
Korea University
This paper deals with data association using three sets of passive linear array sonars (PLAS) geometrically positioned in a Y-shaped configuration, fixed in an underwater environment. The data association problem is directly transformed into a 3-D assignment problem, which is known to be NP hard. For generic passive sensors, it can be solved using conventional algorithms, while in PLAS, it becomes a formidable task due to the presence of bearing ambiguity. Thus, the central issue of the problem in PLAS is how to eliminate the bearing ambiguity without increasing tracking error. To solve this problem, the 3-D assignment algorithm used the likelihood value of only those observed bearing measurements is modified by incorporating frequency information in consecutive time-aligned scans. The region of possible ghost targets is first established by the geometrical relation of PLAS with respect to target. The ghost targets are then confirmed and eliminated by generating multiple observations in consecutive scans. Representative simulations demonstrate the effectiveness of the proposed approach.
--------------------------------------------------
Note added at 6 mins (2005-05-19 18:59:04 GMT)
--------------------------------------------------
Chapter [*] provides a theoretical solution to this problem in the Fourier domain. Here we will express the same concepts in the time domain. Define as follows:
yt Given data.
bt Known filter.
xt Excitation (to be found).
$n_t = y_t \\ -\\ x_t {\\rm *} b_t$ Noise: data minus filtered excitation.
With Z-transforms the problem is given by Y(Z)=B(Z)X(Z)+N(Z). Our primary wish is $N\\approx 0$.Our secondary wish is that X not be infinity as X=Y/B threatens. This second wish is expressed as $\\epsilon X \\approx 0$and is called ``stabilizing\" or ``damping.\" In the Fourier domain the wishes are
\\begin{eqnarray} Y & \\approx & B X \\ 0 & \\approx & \\epsilon X\\end{eqnarray} (50)
(51)
The formal expression of the regression is
\\begin{eqnarray} \\min_X \\ \\ ( \\ \\vert\\vert Y-BX \\vert\\vert \\ +\\ \\epsilon^2 \\vert\\vert X \\vert\\vert \\ )\\end{eqnarray} (52)
In the time domain the regression is much more explicit:
\\begin{displaymath} \\left[ \\begin{array} {c} y_0 \\ y_1 \\ y_2 \\ y_3... ...x_2 \\ x_3 \\ x_4 \\ x_5 \\ x_6 \\end{array} \\right]\\end{displaymath} (53)
where ``$\\cdot$\'\' denotes a zero. Since it is common to add $\\epsilon \\bold I$ to an operator to stabilize it, I prepared subroutine ident() for this purpose. It is used so frequently that I coded it in a special way to allow the input and output to overlie one another.
subroutine ident( adj, add, epsilon, n, pp, qq )
integer i, adj, add, n
real epsilon, pp(n), qq(n) # equivalence (pp,qq) OK
if( adj == 0 ) {
if( add == 0 ) { do i=1,n { qq(i) = epsilon * pp(i) } }
else { do i=1,n { qq(i) = qq(i) + epsilon * pp(i) } }
}
else { if( add == 0 ) { do i=1,n { pp(i) = epsilon * qq(i) } }
else { do i=1,n { pp(i) = pp(i) + epsilon * qq(i) } }
}
return; end
We can use any convolution routine we like, but for simplicity, I selected contrunc() so the output would be the same length as the input. The two operators ident() and contrunc() could be built into a new operator. I found it easier to simply cascade them in the deghosting subroutine deghost() below.
# deghost: min |rrtop| = | y - bb (contrunc) xx |
# x |rrbot| | 0 - epsilon I xx |
subroutine deghost( eps, nb,bb, n, yy, xx, rr, niter)
integer iter, nb, n, niter
real bb(nb), yy(n), eps # inputs. typically bb=(1,-2,1)
real xx(n), rr(n+n) # outputs.
temporary real dx(n), sx(n), dr(n+n), sr(n+n)
call zero( n, xx)
call copy( n, yy, rr(1 )) # top half of residual
call zero( n , rr(1+n)) # bottom of residual
do iter= 0, niter {
call contrunc(1,0,1,nb,bb, n,dx,n,rr); call ident(1,1,eps, n,dx,rr(1+n))
call contrunc(0,0,1,nb,bb, n,dx,n,dr); call ident(0,0,eps, n,dx,dr(1+n))
call cgstep( iter, n,xx,dx,sx, _
n+n,rr,dr,sr)
}
return; end
http://sepwww.stanford.edu/sep/prof/pvi/ls/paper_html/node19...
The marine ghost presents a problem that is essentially insoluble; but because it is always with us, we need to understand how to do the best we can with it. Even if an airgun could emit a perfect impulse, the impulse would reflect from the nearby water surface, thereby giving a second pulse of opposite polarity. The energy going down into the earth is therefore a doublet when we would prefer a single pulse. Likewise, hydrophones see the upcoming wave once coming up, and an instant later they see the wave with opposite polarity reflecting from the water surface. Thus the combined system is effectively a second derivative wavelet (1,-2,1) that is convolved with signals of interest. Our problem is to remove this wavelet by deconvolution. It is an omnipresent problem and is cleanly exposed on marine data where the water bottom is hard and deep.
Theoretically, a double integration of the second derivative gives the desired pulse. A representation in the discrete time domain is the product of (1-Z)2 with $1+2Z+ 3Z^2+ 4Z^3+ 5Z^4+ \cdots $, which is 1. Double integration amounts to spectral division by $-\omega^2$.Mathematically the problem is that $-\omega^2$ vanishes at $\omega=0$.In practice the problem is that dividing by $\omega^2$ where it is small amplifies noises at those low frequencies. (Inversion theorists are even more frustrated because they are trying to create something like a velocity profile, roughly a step function, and they need to do something like a third integration.) Old nuts like this illustrate the dichotomy between theory and practice.
--------------------------------------------------
Note added at 5 mins (2005-05-19 18:57:58 GMT)
--------------------------------------------------
sepwww.stanford.edu/sep/ prof/pvi/ls/paper_html/node19.html
--------------------------------------------------
Note added at 5 mins (2005-05-19 18:58:32 GMT)
--------------------------------------------------
Data Association for
Deghosting in Y-Shaped
Passive Linear Array Sonars
BONHWA KU
JEHAN YOON
Korea University
DAVID K. HAN
Johns Hopkins University
HANSEOK KO, Senior Member, IEEE
Korea University
This paper deals with data association using three sets of passive linear array sonars (PLAS) geometrically positioned in a Y-shaped configuration, fixed in an underwater environment. The data association problem is directly transformed into a 3-D assignment problem, which is known to be NP hard. For generic passive sensors, it can be solved using conventional algorithms, while in PLAS, it becomes a formidable task due to the presence of bearing ambiguity. Thus, the central issue of the problem in PLAS is how to eliminate the bearing ambiguity without increasing tracking error. To solve this problem, the 3-D assignment algorithm used the likelihood value of only those observed bearing measurements is modified by incorporating frequency information in consecutive time-aligned scans. The region of possible ghost targets is first established by the geometrical relation of PLAS with respect to target. The ghost targets are then confirmed and eliminated by generating multiple observations in consecutive scans. Representative simulations demonstrate the effectiveness of the proposed approach.
--------------------------------------------------
Note added at 6 mins (2005-05-19 18:59:04 GMT)
--------------------------------------------------
Chapter [*] provides a theoretical solution to this problem in the Fourier domain. Here we will express the same concepts in the time domain. Define as follows:
yt Given data.
bt Known filter.
xt Excitation (to be found).
$n_t = y_t \\ -\\ x_t {\\rm *} b_t$ Noise: data minus filtered excitation.
With Z-transforms the problem is given by Y(Z)=B(Z)X(Z)+N(Z). Our primary wish is $N\\approx 0$.Our secondary wish is that X not be infinity as X=Y/B threatens. This second wish is expressed as $\\epsilon X \\approx 0$and is called ``stabilizing\" or ``damping.\" In the Fourier domain the wishes are
\\begin{eqnarray} Y & \\approx & B X \\ 0 & \\approx & \\epsilon X\\end{eqnarray} (50)
(51)
The formal expression of the regression is
\\begin{eqnarray} \\min_X \\ \\ ( \\ \\vert\\vert Y-BX \\vert\\vert \\ +\\ \\epsilon^2 \\vert\\vert X \\vert\\vert \\ )\\end{eqnarray} (52)
In the time domain the regression is much more explicit:
\\begin{displaymath} \\left[ \\begin{array} {c} y_0 \\ y_1 \\ y_2 \\ y_3... ...x_2 \\ x_3 \\ x_4 \\ x_5 \\ x_6 \\end{array} \\right]\\end{displaymath} (53)
where ``$\\cdot$\'\' denotes a zero. Since it is common to add $\\epsilon \\bold I$ to an operator to stabilize it, I prepared subroutine ident() for this purpose. It is used so frequently that I coded it in a special way to allow the input and output to overlie one another.
subroutine ident( adj, add, epsilon, n, pp, qq )
integer i, adj, add, n
real epsilon, pp(n), qq(n) # equivalence (pp,qq) OK
if( adj == 0 ) {
if( add == 0 ) { do i=1,n { qq(i) = epsilon * pp(i) } }
else { do i=1,n { qq(i) = qq(i) + epsilon * pp(i) } }
}
else { if( add == 0 ) { do i=1,n { pp(i) = epsilon * qq(i) } }
else { do i=1,n { pp(i) = pp(i) + epsilon * qq(i) } }
}
return; end
We can use any convolution routine we like, but for simplicity, I selected contrunc() so the output would be the same length as the input. The two operators ident() and contrunc() could be built into a new operator. I found it easier to simply cascade them in the deghosting subroutine deghost() below.
# deghost: min |rrtop| = | y - bb (contrunc) xx |
# x |rrbot| | 0 - epsilon I xx |
subroutine deghost( eps, nb,bb, n, yy, xx, rr, niter)
integer iter, nb, n, niter
real bb(nb), yy(n), eps # inputs. typically bb=(1,-2,1)
real xx(n), rr(n+n) # outputs.
temporary real dx(n), sx(n), dr(n+n), sr(n+n)
call zero( n, xx)
call copy( n, yy, rr(1 )) # top half of residual
call zero( n , rr(1+n)) # bottom of residual
do iter= 0, niter {
call contrunc(1,0,1,nb,bb, n,dx,n,rr); call ident(1,1,eps, n,dx,rr(1+n))
call contrunc(0,0,1,nb,bb, n,dx,n,dr); call ident(0,0,eps, n,dx,dr(1+n))
call cgstep( iter, n,xx,dx,sx, _
n+n,rr,dr,sr)
}
return; end
http://sepwww.stanford.edu/sep/prof/pvi/ls/paper_html/node19...
4 KudoZ points awarded for this answer.
Comment: "Graded automatically based on peer agreement."
+3
3 mins
antifantasma
Si estamos hablando de la atenuaci¢n en hidrofon¡a
Peer comment(s):
agree |
George Rabel
: who you gonna call?
1 min
|
gracias George, seguramente a los mocosos
|
|
neutral |
moken
: ¡Hola Ernesto! No opino sobre la respuesta pero, ¿viste el historial del colega? 404 preguntas hechas, 95 de ellas sin cerrar (la mayoría de la cerradas, por el 'robot'), contra 6 intentos de ayudar un compañero. Creo que es un récord. :O) :O)
1 hr
|
Hola, µlvaro, los hay peores, creo
|
|
agree |
Hector Aires
: Agrí. con Álvaro y con Ernesto, hay mucho peores. Hay quien jamás ha contestado algo aunque no fuera aceptado. Por mi parte, gustoso haría un listado de "amigos y colegas" y los pondría en una vitrina/escaparate/vidriera sometidos al escarnio público.
4 hrs
|
gracias H‚ctor. Me has dado la idea de montar una verduler¡a cercana a la vitrina
|
|
neutral |
Gabo Pena
: that's funny George!
6 hrs
|
agree |
Cecilia Della Croce
1 day 22 hrs
|
gracias Cecilia
|
6 hrs
limpiar la señal- remover resonancias
Ghostbusters
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